5d^2+9d+5=3d^2

Solution for 5d^2+9d+5=3d^2 equation:

5d^2+9d+5=3d^2

We move all terms to the left:

5d^2+9d+5-(3d^2)=0

determiningTheFunctionDomain
5d^2-3d^2+9d+5=0

We add all the numbers together, and all the variables

2d^2+9d+5=0

a = 2; b = 9; c = +5;
Δ = b2-4ac
Δ = 92-4·2·5
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{41}}{2*2}=\frac{-9-\sqrt{41}}{4}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{41}}{2*2}=\frac{-9+\sqrt{41}}{4}
$